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olganol [36]
3 years ago
6

Find the center and radius of the sphere whose equation is given by x2+y2+z2−2x−4y+8z+17=0x2+y2+z2−2x−4y+8z+17=0.

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
We know that
the equation of a sphere is
(x-h)²+(y-k)²+(z-l)²=r²
where (h,k,l) is the center and r is the radius

we have
x²+y²+z²<span>−2x−4y+8z+17=0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²+2x)+(y²-4y)+(z²+8z)=-17
<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=-17+1+4+16
(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=4

Rewrite as perfect squares

(x+1)²+(y-2²)+(z+4)²=4

(x+1)²+(y-2²)+(z+4)²=2²

the center is the point (-1,2,-4) and the radius is 2 units




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from the top of a tree the angle of depression of a rock on the ground is 49 degrees. If the tree is 18.5 m tall, how far is the
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Step-by-step explanation:

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Download docx
4 0
3 years ago
How do u write 5(2x - 1) in a distributive property
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Step-by-step explanation:

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It can be written as:

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HOPE THIS HELPS

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