To solve this problem, you will first want to convert 5 pounds into ounces. To do this, first determine how many ounces is in 1 pound.
There are 16 ounces in 1 pound, so to convert 5 pounds into ounces, you simply have to multiply 5 × 16. This will give you 80 ounces total.
Allie give 12 ounces away, so you must first subtract 12 ounces from your total (80 ounces). 80 - 12 gives us 68 ounces.
Allie then divides the trail mix up into 4 ounce portions. To figure out how many small bags she can make, you simply divide your new total (68 ounces) by 4.
68 ÷ 4 = 17
Allie made 17 small bags.
The answer is a = 
Step-by-step explanation:
<em>1. Convert the mixed fraction to an improper fraction</em>
To find the numerator, multiply the denominator by the whole number and add the numerator to it.
The denominator remains the same.
So, 2
will be 
<em>2. Now the equation is,</em>
a -
a =
+
a
<em>3. Take LCM on both sides. </em>
For the left side, multiply the first fraction by
and multiply the second fraction by 
a -
a = 
<em>4. Solve by making a the subject</em>
= 
= 
=10+8a
= 10 + 8a
a = 2(10 + 8a)
a = 20 + 16a
a-16a = 20
-15a = 20
a = 
a = 
Therefore, the answer is a = 
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Answer:
Step-by-step explanation:
-1/2
Answer:
2090
Step-by-step explanation:
0.06 × 2000 =120 therefore 120 × 24 =2088. and round off to the cent
Answer:
The correct order is:
a
c
d
b
Step-by-step explanation:
First, let's write 1/x in a convenient way for us:
a) Substitute 1/x = p/q, to obtain x = 1/(1/x) = 1/(p/q) = q/p.
Now we assume that 1/x is rational (we want to prove that this implies that x will be also rational and because we know that x is irrational assuming that 1/x is rational will lead to an incongruence), then:
c. If 1/x is rational, then 1/x = p/q for some integers p and q with q ≠ 0. Observe that p is not 0 either, because 1/x is not 0.
Now we know that we can write x as a quotient of two integers, we need to imply that, then the next one is:
d) Observe that x is the quotient of two integers with the denominator nonzero.
And that is the definition of rational, then we end with:
b) Hence x is rational.
Which is what we wanted to get.