3 years ago

What is the slope of the equation y – 3 = –4(x – 5)?e of the equation y – 3 = –4(x – 5)?

Mathematics

2 answers:

anygoal [31]3 years ago

8 0

Answer:

-4

Step-by-step explanation:

Len [333]3 years ago

6 0

Answer:

The slope of the equation y-3=-4(x-5) is -4.

Step-by-step explanation:

This equation is written in point-slope form: y-y₁=m(x-x₁), where "m" is the slope or the equations. In the equation y-3=-4(x-5), the -4 stands in the "m", or slope, spot, so the sope of this equation is -4.

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In a circle, a 90 degree sector has area of 36pi ftsqd. what is the radius of the circle?

lukranit [14]

$\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
\theta =90\\
A=36\pi 
\end{cases}\implies 36\pi =\cfrac{90\pi r^2}{360}
\\\\\\
\cfrac{36\pi }{90\pi }=\cfrac{r^2}{360}\implies \cfrac{2}{5}=\cfrac{r^2}{360}\implies \cfrac{360\cdot 2}{5}=r^2\implies 144=r^2
\\\\\\
\sqrt{144}=r\implies 12=r$