![\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=6\\ h=15 \end{cases}\implies \begin{array}{llll} V=\pi (6)^2(15)\implies V=540\pi \\\\\\ V\approx 1696.46 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%20V%3D%5Cpi%20r%5E2%20h~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D6%5C%5C%20h%3D15%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20V%3D%5Cpi%20%286%29%5E2%2815%29%5Cimplies%20V%3D540%5Cpi%20%5C%5C%5C%5C%5C%5C%20V%5Capprox%201696.46%20%5Cend%7Barray%7D)
notice, the cup can take that much in cm³, so it can surely take 1620 just fine.
PSF: y - y₁ = m(x - x₁)
Standard Form: ax + by = c
Point Slope Form Standard Form
1). y - 3 = -4(x + 8) 2). y = -4x - 29
y - 3 = -4x - 32 + 4x + 4x
+ 3 + 3 ---------------------------------
----------------------------- 4x + y = -29
y = =4x - 29
This isnt 30 points this is 15
It would be 90m3 because all the angles are the same