What is the measure of arc ADB?
The measure of the arc for this case is given by the following angle:
theta = 360-90
theta = 270 degrees
What is the length of arc ADB?
The arc length is given by:
s = R * theta
Substituting values:
s = 15 * (270 * (pi / 180))
s = 70.69 m
What is the area of the shaded region?
The area of the shaded region is:
A = (s' / s) * (pi) * (r ^ 2)
Substituting values:
A = (270/360) * (3.14) * (15 ^ 2)
A = 529,875 m ^ 2
Answer :
(64)2
Explaination:
(6)4 x 2
68
DC-10
At t=0 the altidude is 4500 feet
It's descending at a rate of 150 feet per minute, then each 5 minutes it descends (150 feet/min)(5 min)=750 feet. Then:
At t=5 the altitude is 4500 feet-750 feet=3750 feet
At t=10 the altitude is 3750 feet-750 feet=3000 feet
727
At t=0 the altidude is 600 feet
It's climbing at a rate of 75 feet per minute, then each 5 minutes it climbs (75 feet/min)(5 min)=375 feet. Then:
At t=5 the altitude is 600 feet+375 feet=975 feet
At t=10 the altitude is 975 feet+375 feet=1350 feet
The graph with these characteristics is Graph B.
Answer: The graph B shows when the two planes will be at the same altitude
![\bf \cfrac{\sqrt{16}}{2}-\sqrt[4]{16}\implies \cfrac{4}{2}-\sqrt[4]{2^4}\implies 2-2\implies 0](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ccfrac%7B%5Csqrt%7B16%7D%7D%7B2%7D-%5Csqrt%5B4%5D%7B16%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B2%7D-%5Csqrt%5B4%5D%7B2%5E4%7D%5Cimplies%202-2%5Cimplies%200%20)
recall that the whole numbers is the set of 0,1,2.... onwards
![\bf -\sqrt{36}+\sqrt[3]{125}\implies -\sqrt{6^2}+\sqrt[3]{5^3}\implies -6+5\implies -1](https://tex.z-dn.net/?f=%20%5Cbf%20-%5Csqrt%7B36%7D%2B%5Csqrt%5B3%5D%7B125%7D%5Cimplies%20-%5Csqrt%7B6%5E2%7D%2B%5Csqrt%5B3%5D%7B5%5E3%7D%5Cimplies%20-6%2B5%5Cimplies%20-1%20)
recall that integers are just whole numbers, positive or negative.
First solve one of the two equations (whichever is easier) for either x or y, whichever variable is easier. Let's say you solved for x. Then plug what x equals into the 2nd equation as x. So if you got x = 2y + 1, plug that into your other equation and solve for y (you should get a number value).
Now take whatever y equals and plug that back into what you got when you solved for x (the x = 2y + 1) to get what x equals.
