It’s the first one -13–16
Answer:
#1.---60% #2.---$12.60 per hour
Step-by-step explanation:
#1. Since It was originally $50 you have 50% already, so what I did was I multiplied 50 by 2. this got me 100 which is a simpler way to calculate by. 50 to 80 dollars is a $30 change, so multiply that by 2 and you get 60. 60 will be your percent of change. You can double check this by multiplying 50 by .60, the answer will be 30 and 50+30=80
#2 Since Tyler starts off with $12 per hour with a 5% increase you will need to multiply 12*.05 this will get you the answer of 0.6 you then need to add $12, since that was his original payment. 12+0.6=12.60, so his final payment would by $12.60 per hour
5/6 is closest to 1 because it it 1/6 away from 1 and is 5/6 away from 0 and is 2/6 away from 1/2 (referring 1/2 as 3/6) Hope this helps!
Answer:
Step-by-step explanation:
Hello!
I'll express all the given percentages as probabilities:
Given the events:
Banking online (Bo)
Under the age of 50 (<50)
P(Bo)= 0.30
P(<50)= 0.40
P(Bo ∩ <50)= 0.25
1) What percentage of adults do not conduct their banking online?
The event "adults that do not conduct their baking online" is the complement of the event "adults that conduct their baking online" Symbolically 
P()= 1 - P(Bo)= 1 - 0.30 = 0.70
2) What type of probability is 25%?
The probability P(Bo ∩ <50)= 0.25 is a joint probability, it indicates the intersection between both events.
3) Construct a contingency table showing all joint and marginal probabilities.
Check attachment.
4) What is the probability that an individual conducts banking online given that the individual is under the age of 50?
Symbolically:
P(Bo/<50)= <u> P(Bo ∩ <50) </u> = <u> 0.25 </u> = 0.625
P(<50) 0.40
I hope it helps!
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
