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Svetlanka [38]
3 years ago
13

Evaluate the expression (-32)^3/5

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0

Answer:

-8

Step-by-step explanation:

x^(m/n)=\sqrt[n]{x}^m

(-32)^(3/5)

=\sqrt[5]{(-32)} ^3

=(-2)^3

=-8

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Solve the inequality 4y + 3 > 2y + 14​
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PLEASE HELP. WILL GIVE BRAINLIEST !! Find the cross product <-1, -3, -8> x <7,4, -5>. Is the resulting vector perpen
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Answer:

Answer:

The cross product is 47 i - 61 j + 17 k.

Step-by-step explanation:

Given that-

a = < -1, -3, -8 > , b = < 7, 4, -5 >

The cross product is

a × b =\begin{gathered}\left[\begin{array}{ccc}i&j&k\\-1&-3&-8\\7&4&-5\end{array}\right]\end{gathered}⎣⎢⎡i−17j−34k−8−5⎦⎥⎤

        = i ( - 3 × -5 - 4 × -8 ) - j ( -1 × -5 - (-8) × 7 ) + k ( -1 × 4 - 7 × -3 )

        = i ( 15 + 32 ) -j ×( 5 + 56 ) + k ( -4 + 21 )

        = i ( 47) - j (61 ) + k (17)

        = 47 i -61 j + 17 k

As we know that if two vectors A & B are perpendicular then

A . B = 0

So here only the given vector b = < 7,4, -5> is perpendicular to the resulting vector .

Step-by-step explanation:

47, -61, 71>; yes

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Answer:

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Step-by-step explanation:

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