✿————✦————✿————✦————✿
The answer is: <u>2(k2−4k)(2c+5)</u>
✿————✦————✿————✦————✿
Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
✿————✦————✿————✦————✿
Answer:
2
Step-by-step explanation:
Answer:
See below, please
Step-by-step explanation:
The right:


The left:

So, after comparing the right side and the left side of this equation, we know
1)

2)

3)

So,

Subtract what is to the right of the equal sign form both side of the equation but any way the answer is 0