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mart [117]
3 years ago
13

How might an organization like Pew Research obtain an accurate estimate of the number of cell-phone only households in the first

place? What kind of sample would you need to get this estimate? How would you contact this sample?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

a) Sample of households using cell-phone only in a particular region or in a country.

b) It has to be Systematic sampling techniques

Step-by-step explanation:

a) Since the goal of the organization is to estimate the number of cell phone only households. Only households that uses cell-phone only is the appropriate population to sample from. The first step is to identify the households that fall into the population of interest. Then number them systematically and sample from the frame.

b) The moment an household is selected into the sample from the frame, the researcher can visit to conduct the survey. Or, he or she can use other method of data collection such as phoning the household before physical visit, etc.

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3>-6

Step-by-step explanation:

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Answer:

46.03 = 46.030

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3 years ago
Shelby mixes a 25% bleach solution with 5 cups of a 10% bleach solution, resulting in a 20% bleach solution. The table shows the
german

Answer:

10

Step-by-step explanation:

We will use a system of equations to solve this.  We do not know how much of the 25% bleach solution is used; we will use x to represent this.  We know that 5 cups of the 10% solution was used.  We do not know how much of the resulting solution we have; we will use y to represent this.  This gives us the equation

x+5 = y

Using the decimal forms of the percentages for each solution, we have 0.25x (25% solution for x cups), 0.1(5) (10% solution for 5 cups) and 0.2y (20% solution for y cups); this gives us the equation

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This gives us the system

\left \{ {{x+5=y} \atop {0.25x+0.1(5)=0.2y}} \right.

To use elimination, we will make the coefficients of x the same by multiplying the top equation by 0.25:

\left \{ {{0.25(x+5=y)} \atop {0.25x+0.5=0.2y}} \right. \\\\\left \{ {{0.25x+1.25=0.25y} \atop {0.25x+0.5=0.2y}} \right.

We will now subtract the second equation from the first:

\left \{ {{0.25x+1.25=0.25y} \atop {-(0.25x+0.5=0.2y)}} \right. \\\\0.75 = 0.05y

Divide both sides by 0.05:

0.75/0.05 = 0.05y/0.05

15 = y

There were 15 cups of the resulting 20% solution.  Substituting this into the first equation, we have

x+5=15

Subtract 5 from each side:

x+5-5=15-5

x = 10

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