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3 years ago

What is the value of x in the figure below? In this diagram

Mathematics

1 answer:

Pani-rosa [81]3 years ago

3 0

Answer:

(B) x=\sqrt{30}

Step-by-step explanation:

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Micah pays 54$ for an item originally priced 60$. What percentage of the original price was his discount?

pantera1 [17]

Answer: The percentage of the original price was his discount = 10%

Step-by-step explanation:

Given: original price = $60

Price after discount = $54

Discount = Price after discount - original price

= $ (60-54) = $6

The percentage of the original price was his discount = $\dfrac{Discount}{Original\ price}\times100$

$=\dfrac{6}{60}\times100\%\\\\=\dfrac{1}{10}\times100\%\\\\=10\%$

Hence, the percentage of the original price was his discount = 10%

3 0

3 years ago

What is the distance between the points (-7, 5) and (-2, -7)

harkovskaia [24]

Answer:

The distance between those points is 13.

Step-by-step explanation:

1. (x2-x1) = (-2 - -7) = 5

2. (y2-y1) = (-7 - 5) = -12

3. (5)2 + (-12)2 = 25 + 144 = 169

4. √169 = 13

5. 13

7 0

3 years ago

What's the answer to this??

Evgen [1.6K]

The variable "x" equals 7

3 0

3 years ago

Question 17 please help

kramer

$\sqrt{9x^2} / \sqrt{18y^2}$
after taking sqrt both side

3x/ $\sqrt{9*2y^2}$

3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y

Answer is A

8 0

3 years ago

. Which ordered pairs in the form (x, y) are solutions to the equation 7x – 5y = 28?

Brut [27]

we know that

If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation

we have the equation

$7x-5y=28$

Let's verify all the cases to determine the solution to the problem.

case A) point $(-6,-14)$

Substitute the values of x and y in the equation

$x=-6\\y=-14$

$7(-6)-5(-14)=28$

$-42+70=28$

$28=28$ -------> is true

therefore

The point $(-6,-14)$ is a solution of the equation

case B) point $(-1,-7)$

Substitute the values of x and y in the equation

$x=-1\\y=-7$

$7(-1)-5(-7)=28$

$-7+35=28$

$28=28$ -------> is true

therefore

The point $(-1,-7)$ is a solution of the equation

case C) point $(4,10)$

Substitute the values of x and y in the equation

$x=4\\y=10$

$7(4)-5(10)=28$

$28-50=28$

$-22=28$ -------> is not true

therefore

The point $(4,10)$ is not a solution of the equation

case D) point $(7,9)$

Substitute the values of x and y in the equation

$x=7\\y=9$

$7(7)-5(9)=28$

$49-45=28$

$4=28$ -------> is not true

therefore

The point $(7,9)$ is not a solution of the equation

therefore

the answer is

$(-6,-14)$

$(-1,-7)$

8 0

3 years ago

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