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lesya692 [45]
3 years ago
15

Is the equation 4 x^2 + 2 x - 4=5 x^2 linear or​ quadratic?

Mathematics
2 answers:
andrew11 [14]3 years ago
4 0

Answer:Quadratic because I think so and because it has fours in it so yeah good luck :p

SSSSS [86.1K]3 years ago
4 0

Answer:

Linar

Step-by-step explanation:

it only has one variable

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Which shows how to solve the equation 3/4 X=-6 for x in one step?<br>​
marshall27 [118]

Answer:

x=-8

Step-by-step explanation:

You have to divide by 3/4 each side

Since it's a fraction it will multiplying by the recripocal on each side which will be 4/3.

If you multiple 4/3 to -6 the answer should be -8. So X would equal -8.

7 0
3 years ago
Which equation represents a line which is parallel to the line x-3y=15?
LekaFEV [45]

Step-by-step explanation:

Two lines that are parallel have the same slope. If we make x - 3y = 15 in to slope-intercept form it'll be like this:

x - 3y = 15 \\ -3y = 15 - x \\ y = \frac{15 - x}{-3} \\ y = \frac{1}{3}x - 5

Now we know y = \frac{1}{3}x - 5\\ as its slope-intercept form we can see the slope is \frac{1} {3}\\.

y = \frac{1}{3}x + 4\\ has the same slope as y = \frac{1}{3}x - 5\\ so they are both parallel.

<h3>Answer:</h3>

y = \frac{1}{3}x + 4\\

6 0
3 years ago
Trigonometry
xxTIMURxx [149]

Answer:

9 units

Step-by-step explanation:

Since they lie on the same vertical line,

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14-5 = 9 units

3 0
4 years ago
Log(2)4+log(2)3,16227766/log(2)20+log(2)8
Shalnov [3]
We know the rules of logarithms:
log a^b = b * log a
log a * b = log a + log b
and we know that : 10^0.5 = 3,166227766
So:
( log (2) 4 + log (2) 3,16227766) / ( log (2) 20 + log (2) 8 ) =
= ( 2 + log (2) 10^(0.5) ) / ( log (2) 2 + log (2) 10 + 3 ) =
= ( 2 + 0.5 log (2) 10 ) / ( 1 + log (2) 10 + 3 ) =
= ( 2 + 0.5 log (2) 10 / ( 4 + log (2) 10 ) =
= ( 2 + 0.5 log (2) 10 ) / 2 * ( 2 + 0.5 log (2) 10 ) = ( cancelling )
= 1 / 2  = 0.5 
3 0
3 years ago
Written as a rate, 32 miles in 8 hours would be ____ miles per hour.
Andre45 [30]
The answer to your question would be 4 miles an hour
6 0
3 years ago
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