Answer:
x = 27
Step-by-step explanation:
∠ CAD and ∠ EDF are corresponding angles and are congruent, so
∠ CAD = 2x
The sum of the 3 angles in Δ ABD = 180°
sum the angles and equate to 180
72 + 2x + 2x = 180
72 + 4x = 180 ( subtract 72 from both sides )
4x = 108 ( divide both sides by 4 )
x = 27
Answer:
15 feet
Step-by-step explanation:
Quadrilateral ABCD has a scale facter of 2.5 over the quadrilateral EFGH. The order of ABCD is 60, 40, 30, and x, EFGH has y, z, 12, and 6.
6 times the scale factor of 2.5 is 15, the answer.
Answer:
The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units
Therefore distance s=10 units
Step-by-step explanation:
Given points are (2,10) and (-6, 4) on the coordinate plane
To distance between the given points :
The distance formula is 
units
Let 
,
be the given points (2,10) and (-6, 4) respectively
Now substituting the values in the distance formula we get
Therefore s=10 units
The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units
Answer:
70%
Step-by-step explanation:
49/70 = 0.7
0.7*100 = 70%
Recall the formula for finding the area of a rectangle:
Area = Length × Width
Recall the formula for finding the perimeter of a rectangle:
Perimeter = 2 ( Length + Width )
Given in your problem:
Area = 40 sq. units
Perimeter = 26 units
Required to solve for:
Length (L) and width (W)
• First, substitute the given to the formula:
Area = Length x Width
40 = L × W ⇒ equation number 1
Perimeter = 2 ( Length + Width )
26 = 2 ( L + W ) ⇒ equation number 2
• Simplifying equation number 2,
13 = L + W
• Rearranging the equation,
L = 13 - W ⇒ equation 3
Substituting equation 3 from equation 1:
( equation 1 ) 40 = (L)(W)
( equation 3 ) L = 13 - W
40 = (13 - W) (W)
40 = 13W - W²
( regrouping ) W² - 13W + 40 = 0
( factoring ) (W - 8) (W - 5) = 0
W - 8 = 0 ; W - 5 = 0
W = 8 ; W = 5
Therefore, there are 2 possible values for the width of the rectangle. It can be 8 units or 5 units.
• Now to solve for the length of the rectangle, substitute the two values of width to equation 3.
(equation 3) L = 13 - W
for W = 8 ⇒ L = 13 - 8
L = 5 units
for W = 5 ⇒ L = 13 - 5
L = 8 units
