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ch4aika [34]
3 years ago
9

An artist is creating a large conical sculpture for a park. The cone has a height of 16 m of and a diameter of 25 m. Find the vo

lume the sculpture to the nearest hundredth.
A. 833.33 m3
B. 7,850 m3
C. 2,616.67 m3
D. 209.33 m3
Mathematics
1 answer:
alexdok [17]3 years ago
7 0

Answer:

The answer is B.

Step-by-step explanation:

A=3.14 x 12.5>2

A= 3.14 x 156.25 =490-.625

A= 490.625 x 16m

A= 7, 850 m3

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What is the equation for Pythagorean theorem
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a^2+b^2=c^2

Step-by-step explanation:

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SpyIntel [72]
Ronnie = c
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The distribution of the amount of money spent by students for textbooks in a semester is approximately normal in shape with a me
faust18 [17]

Answer:

Almost 2.5% of the students spent more than $275 in a semester.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 235

Standard deviation = 20

According to the standard deviation rule, almost 2.5% of the students spent more than what amount of money on textbooks in a semester?

95% of the measures are within 2 standard deviation of the mean. The other 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of those are below two standard deviations of the mean and 2.5% are more than two standard deviations above the mean.

235 + 2*20 = $275

Almost 2.5% of the students spent more than $275 in a semester.

4 0
3 years ago
I can’t figure out which formula goes with which sequence. Help……. Please???
Radda [10]

For a geometric sequence

<em>a</em>, <em>ar</em>, <em>ar</em> ², <em>ar</em> ³, …

the <em>n</em>-th term in the sequence is <em>ar</em> <em>ⁿ</em> ⁻ ¹.

The first sequence is

1, 3, 9, 27, …

so it's clear that <em>a</em> = 1 and <em>r</em> = 3, and so the <em>n</em>-th term is 3<em>ⁿ</em> ⁻ ¹.

The second sequence is

400, 200, 100, 50, …

so of course <em>a</em> = 400, and you can easily solve for <em>r</em> :

200 = 400<em>r</em>   ==>   <em>r</em> = 200/400 = 1/2

Then the <em>n</em>-th term is 400 (1/2)<em>ⁿ</em> ⁻ ¹.

Similarly, the other sequences are given by

3rd: … 4 × 2<em>ⁿ</em> ⁻ ¹

4th: … 400 (1/4)<em>ⁿ</em> ⁻ ¹

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