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3 years ago

Please please please help!! 30 points!!

Mathematics

2 answers:

weeeeeb [17]3 years ago

4 0

Answer:

Step-by-step explanation:

4*2*3=24

For every egg you have to chose one toest ( 2 options) and for each toest you can chose 3 different type of meat. So for one tost you have 3 typs of meat, for two tost 6 diferent ways. So for each egg you have 6 ways, and you have 4 eggs. It is 4*6=24

Cerrena [4.2K]3 years ago

4 0

Answer:

Step-by-step explanation:

2*3*4=24

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Please help me thank you I’ll mark Brainly

mrs_skeptik [129]

Answer:

C should be your answer if I'm not right then forgive me please.

Step-by-step explanation:

4 0

3 years ago

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3 (182 + 2) – 172 = -17

IrinaK [193]

Answer:

380≠−17

Step-by-step explanation:

3(182+2)−172 ?= −17

380≠−17

5 0

3 years ago

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Solve X/3 - 2X+1/3 = X-3/5

iren2701 [21]

Answer:

Answer is 3

Step-by-step explanation:

x/3-2x/1+3 =x-3/5

x/3-x/3 = x-3/5

0=x-3/5

0=x-3

3=x

sothat, x = 3 ans

3 0

3 years ago

Tina is saving to buy a notebook computer. She has two options. The first option is to put $200 away initially and save $10 ever

omeli [17]

The correct answers are:

It would take 5 months and she would save $250.

Explanation:

Let m be the number of months.

For the first way of saving, $200 up front and $10 each month, the expression would be

200+10m.

For the second way of saving, $100 up front and $30 each month, the expression would be

100+30m.

Setting them equal gives us the equation

200+10m = 100+30m

Subtract 10m from each side:

200+10m-10m = 100+30m-10m

200 = 100+20m

Subtract 100 from each side:

200-100 = 100+20m-100

100 = 20m

Divide both sides by 20:

100/20 = 20m/20

5 = m

It would take 5 months.

$200 up front and $10 each month for 5 months:

200+10m

200+10(5)

200+50

250

She would save $250.

6 0

3 years ago

Read 2 more answers

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

4 years ago