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3 years ago

The length of a rectangle is twice its width.

Mathematics

1 answer:

mestny [16]3 years ago

7 0

Answer:

<h3>The answer is 60cm</h3>

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

Area of rectangle = l × w

where

l is the length

w is the width

From the question

The length is twice its width is written as

l = 2w

Substitute this into the formula for finding the area of the rectangle

Area = 200 yd²

200 = 2w²

Divide both sides by 2

w² = 100

Find the square root of both sides

width = 10cm

Substitute this value into l = 2w

That's

l = 2(10)

length = 20cm

Perimeter of the rectangle is

2(20) + 2(10)

= 40 + 20

Hope this helps you

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juin [17]

Answer:

From the level of high tide to low tide, it's 18 feet.

Step-by-step explanation:

To find the change in water level, we multiply the rate (3 ft / hr) by the time (6 hrs), obtaining 18 ft.

The water level changes by 18 ft.

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2 years ago

If f(x)=3x+5 and q(x)=0, show that f(x)+q(x)=f(x).

alex41 [277]

Step-by-step explanation:

f(x)=3x+5
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f(x)+q(x)

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3 years ago

Solving the equation

liubo4ka [24]

Answer:

y = 5

Step-by-step explanation:

Step 1: Write equation

-(4y + 2) - (-3y - 6) = -1

Step 2: Solve for <em>y</em>

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Divide both sides by -1: y = 5

Step 3: Check

<em>Plug in y to verify it's a solution.</em>

-(4(5) + 2) - (-3(5) - 6) = -1

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3 years ago

How do I solve surface area

vlabodo [156]

Answer:

Step-by-step explanation:

Surface area is the sum of the areas of all faces (or surfaces) on a 3D shape. A cuboid has 6 rectangular faces. To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.

4 0

2 years ago

Read 2 more answers

How to work it out logically? Question a !!!

Arturiano [62]

Answer:

Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

Step-by-step explanation:

Given the figure with dimensions. we have to find the area of given figure.

Area of figure=ar(1)+ar(2)+ar(3)

Area of region 1 = ar(ANGI)+ar(AIB)

$=L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha$

Area of region 2 = ar(DHBC)

$=2000\times1500\\\\=3000000m^2=300ha$

Area of region 3 = ar(GFEH)

$(2000+1500)\times 1000\\\\=3500000m^2=350ha$

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha

=987.5 ha

Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.

Let the fencing be done through x m downward from B which divides the two into equal area.

⇒ Area of upper part above fencing=Area of lower part below fencing

⇒ $ar(ANGB)+ar(GKLB)=ar(KLCM)+ar(MDCF)\\\\337500+3000x=(3500-x)\times 1000+2000(1500-x)\\\\3375000+3000x=3500000-1000x+3000000-2000x\\\\6000x=315000\\\\x=\frac{315000}{6000}=520.8m$

Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

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3 years ago

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