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marshall27 [118]
3 years ago
9

Write a compound inequality where A quantity x is at least 10 and at most 20

Mathematics
1 answer:
inna [77]3 years ago
3 0
<h3><u>20 ≥ x ≥ 10</u></h3>

would the way to display the compound inequality.

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610mK/s = ______ μK/ms
Blababa [14]

Answer:

  6.10×10² μK/ms

Step-by-step explanation:

When there are trailing zeros in a whole number, the number of significant figures is ambiguous. The given number would ordinarily be considered to have 2 significant figures, as the trailing zero would not count. In order to unambiguously specify the significant figures when there are trailing zeros, the number must be written as a decimal fraction or using scientific notation.

Here, we have 610 mK/s = 0.610 K/s = 610 μK/ms. The latter number can only be shown as having 3 significant digits if it is written in scientific notation:

  6.10×10² μK/ms

3 0
3 years ago
First answer gets a Thanks
fiasKO [112]
The appropriate choice is ...
  B: y = 3.5x

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The number of teaspoons of sugar (y) is 3.5 times the number of tarts (x).
8 0
3 years ago
Math question for 5 graders.
amid [387]

Answer:

1 3/12

Step-by-step explanation:

Oh wait i could read #5 so you make them all have 12 as the denominator then do 78 4/12 - 77 1/12 and you get 1 1/4 or 1 3/12 so then you do  1 3/12 MINUS 77 1/12 and you should get 75 10/12 which is CORRECCTTTTT

THESE ARE THE THREE IN THE TEXT ORDER IN CASE U NEED TO SEE

78 4/12

77 1/12

75 10/12

EVERYTHING IS CORRECTTTTTTTTTTTTTTTTTTTTTT

4 0
3 years ago
Read 2 more answers
Multiply or divide as indicated <br> b^3 x b^-3
Andru [333]

The domain: b\neq0

Method 1.

Use\ a^n\cdot a^m=a^{n+m}\\\\b^3\cdot b^{-3}=b^{3+(-3)}=b^{3-3}=b^0=1

Method 2.

Use\ a^{-n}=\dfrac{1}{a^n}\\\\b^3\cdot b^{-3}=b^3\cdot\dfrac{1}{b^3}=\dfrac{b^3}{b^3}=1

7 0
3 years ago
Find the value of y<br> X=4/y + 2
Oduvanchick [21]

Answer:

Step-by-step explanation:

5 0
3 years ago
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