Answer:
Step-by-step explanation:
![\sqrt[n]{a^m}=a^\frac{m}{n}\\\\144^\frac{3}{2}=144^{1\frac{1}{2}}=144^{1+\frac{1}{2}}\qquad\text{use}\ a^na^m=a^{n+m}\\\\=144^1\cdot144^{\frac{1}{2}}=144\sqrt{144}=144\cdot12=1728](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C144%5E%5Cfrac%7B3%7D%7B2%7D%3D144%5E%7B1%5Cfrac%7B1%7D%7B2%7D%7D%3D144%5E%7B1%2B%5Cfrac%7B1%7D%7B2%7D%7D%5Cqquad%5Ctext%7Buse%7D%5C%20a%5Ena%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D144%5E1%5Ccdot144%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D144%5Csqrt%7B144%7D%3D144%5Ccdot12%3D1728)
Shape A is congruent to Shape B because If you were to rotate one of the two and flip it the would like up and match.
-X+7x-3=0
-7(+-)√(7)^2--4(-1)(#)
(2)(#)
pass me all the picture to can help you
Answer:it didnt
Step-by-step explanation:
Well basically you just have to chose a number of sides for the side length of the square to be and move those many places to get another vertex of the square. For example if we have (-2,3) and we choose the side lengths to be 4 units than you could move 4 places up, down, left, or right to get the other vertices for the square
Hope that helps :)
