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Anuta_ua [19.1K]
4 years ago
15

Martina purchased a prepaid phone card for $20. long distance calls cost 13 cents a minute using this card. Martina used her car

d only once to make a long distance call. If the remaining credit on her card is 17.92, how many minutes did her call last?
Mathematics
2 answers:
Arte-miy333 [17]4 years ago
8 0
The call lasted 16 mins, i used trial and error and the came across 16x.13=2.08 and then you add 17.92 plus 2.08 and that gives you 20
Dima020 [189]4 years ago
7 0
Phone card = $20 
You need to minus 17.92 from 20 = $2.08 
$2.08 / 0.13 = how many minutes 
= 16
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p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.
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Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

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First, let find k. Substitute p= 200

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\frac{200}{2(3) {}^{2} }  = k

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\frac{p}{q {r}^{2} }  =  \frac{100}{9}

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2 years ago
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11,200

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At first we use "BODMAS" rule.

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