The quantity of adults is x, then the quantity of children are 2x, the quantity of students is 333-x-2x=333-3x. The charge from all adults is 12x, students gave 7*(333-3x), children gave 5*2x=10x, the sum of all money is 2422

12x+ 7(333-3x)+10x=2422

12x+2331-21x+10x=2422

2331+x=2422

x=91- the amount of adults

1) 91*2=182- the amount of children

333-91-182= 60- the amount of students

6 0

3 years ago

a box contains 4 yellow, 5 green and 3 blue balls. find the probability of obtaining a yellow ball in a single random draw.

Alex

Notice that the box has a total os 4 + 5 + 3 = 12 balls, since there are 4 that are yellow, then, the probability to randomly obtaining a yellow ball in a single draw is:

$P(Yellow)=\frac{\text{ number of yellow balls}}{\text{total number of balls}}=\frac{4}{12}=0.33$

therefore, the probability is 0.33 = 33%

7 0

1 year ago

Solve for X<br> Solve for X

sammy [17]

X = 9

Work:
5x-3+48+90=180 (sum)
-3+48+90=135
135+5x=180
subtract 135 from 135 and 180 and that gives you 45
5x=45
divide each side by 5
x=9

3 0

3 years ago

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