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The probability that a bone density test score greater than 0.49 calculated using the Zscore formula is 0.312
Given the Parameters :
- Mean, μ = 0
- Standard deviation, σ = 1
- Score, X = 0.49
<u>Recall, the Z score formula</u> :
- Zscore = (X - mean) / standard deviation
Zscore = (0.49 - 0) / 1 = 0.49
<u>The Probability can be expressed thus</u> :
P(Z > 0.49) = 1 - P(Z < 0.49)
Using a probability calculator or normal distribution table ;
P(Z < 0.49) = 0.68793
P(Z > 0.49) = 1 - 0.68793
P(Z > 0.49) = 0.31207
Therefore, the P(Z > 0.49) will be 0.312
Learn more :brainly.com/question/8165716
