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iris [78.8K]
3 years ago
7

Y=-x 5x+2y=9 BRAINLIEST REWARDED

Mathematics
2 answers:
Blizzard [7]3 years ago
6 0
<span>Y=-x</span>→<span>
5x+2y=9

5x+2(-x)=9</span><span>
5x-2x=9
3x=9
x=9</span>÷3
x=3
timama [110]3 years ago
3 0
5x+2-x=9
     -2     -2
5x-x=7
4x=7
---  ---
4     4

X= 1.75
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Can someone please answer this !?!!
snow_tiger [21]

Answer:

midpoint is the answer.....

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3 years ago
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Raj measures the height of 70 plants calculate the estimate of the mean height of the plants
noname [10]

The mean height of plants is 44.07cm.

Given that a raj measures the height of 70 plants which is shown in the table in the image attached below.

The mean is defined as the mean value equal to the ratio of the total number of a given set of values ​​to the total number of values ​​contained in that set.

Firstly, we will find the midpoint of the height by using the formula

(upper limit +lower limit)/2

When h is 10<h<20 then the midpoint is

x₁=(10+20)/2

x₁=15

When h is 20<h<0 then the midpoint is

x₂=(20+40)/2

x₂=30

When h is 40<h<50 then the midpoint is

x₃(40+50)/2

x₃=45

When h is 50<h<60 then the midpoint is

x₄=(50+60)/2

x₄=55

When h is 60<h<90 then the midpoint is

x₅=(60+90)/2

x₅=75

Now, we will find the mean height by using the formula

x=(f₁x₁+f₂x₂+f₃x₃+f₄x₄+f₅x₅)/(Σfi)

Here, f₁=7,f₂=15,f₃=27,f₄=13,f₅=8

and Σfi=7+15+27+12+8=70

Substitute these values in the formula, we get

x=(7×15+15×30+27×45+12×55+8×75)/70

x=(105+450+1215+715+600)/70

x=(3085)/70

x=44.07

Hence,  the estimate of the mean height of the plants when raj measures the height of 70 plants is 44.07cm.

Learn more about mean from here brainly.com/question/3491195

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8 0
1 year ago
Paula has a box in the shape of a rectangular prism. The box has a length of 40 inches, a height of 24 inches, and a width of 18
zepelin [54]

Answer:

17,280 in^3 (cubic inches)

Step-by-step explanation:

40(L)x24(H)x18 (W)

6 0
3 years ago
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In the isosceles trapezoid ABCD, find the value of x.
Semenov [28]

Answer:

15

Step-by-step explanation:

3x+15=60

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6 0
3 years ago
The figure is made up of a hemisphere and a cylinder.
Goryan [66]
Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: \pi \approx 3.14
V (volume) = ?

Solving:(<span>Cylinder volume)
</span>V = h* \pi *r^2
V = 8*3.14*5^2
V = 8*3.14*25
\boxed{ V_{cylinder}  = 628\:cm^3}

<span>Note: Now, let's find the volume of a hemisphere.
</span>
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4 * \pi *  \frac{r^3}{3}, but we have a hemisphere, so the formula will be half the volume of the hemisphere V =  \frac{1}{2}  * 4 * \pi *  \frac{r^3}{3} &#10;

Formula: (<span>Volume of the hemisphere)
</span>V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}

Solving:
V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}
V =  \frac{1570}{6}
\boxed{V_{hemisphere}\approx 261.6\:cm^3}


<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
</span>
Volume of the figure = cylinder volume + hemisphere volume
Volume of the figure = 628 cm³ + 261.6 cm³
\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark
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