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goldfiish [28.3K]

3 years ago

7

Find the value of x. A. 10 B. 9 C. 5.5 D. 4.5

1 answer:

max2010maxim [7]3 years ago

7 0

Answer:

c

Step-by-step explanation:

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Write a possible third degree polynomial with integer coefficient that have zeros: 1 2i, -4. Assume the leading coefficient to b

jasenka [17]

Answer:

The polynomial is:

$p(x) = x^3 + 2x^2 - 3x + 20$

Step-by-step explanation:

A third degree polynomial can be written in function of it's zeros $x_1, x_2, x_3$ the following way:

$p(x) = a(x - x_1)(x - x_2)(x - x_3)$

In which a is the leading coefficient.

Integer coefficient that have zeros: 1+2i, 1-2i, -4

Leading coefficient: 1

So

$p(x) = 1(x - (1+2i))(x - (1-2i))(x - (-4))$

$p(x) = (x - 1 -2i)(x - 1 + 2i)(x + 4)$

$p(x) = ((x-1)^2 - (2i)^2)(x + 4)$

$p(x) = (x^2 - 2x + 1 - 4i^2)(x + 4)$

Since $i^2 = -1$

$p(x) = (x^2 - 2x + 1 + 4)(x + 4)$

$p(x) = (x^2 - 2x + 5)(x + 4)$

$p(x) = x^3 + 4x^2 - 2x^2 - 8x + 5x + 20$

$p(x) = x^3 + 2x^2 - 3x + 20$

3 0

3 years ago

Choose the equation that has solutions (5,7) and (8,13).

Alekssandra [29.7K]

<h2>Answer:y=2x-3</h2>

Step-by-step explanation:

$(x_{1},y_{1})$ is called solution of a equation if $(x_{1},y_{1})$ satisfies the equation.

Consider the equation $y=2x-3$ ,

For point $(5,7)$ ,

$LHS=y=7$

$RHS=2x-3=2(5)-3=10-3=7$

So, $RHS=LHS$

The point $(5,7)$ satisfies the equation.

For point $(8,13)$ ,

$LHS=y=13$

$RHS=2x-3=2(8)-3=16-3=13$

So, $RHS=LHS$

The point $(8,13)$ satisfies the equation.

So,both the points satisfy the equation $y=2x-3$

5 0

3 years ago

16.) (2x⁵y²)(4xy³) + (x⁴y⁴)(3x²y)

daser333 [38]

Again, I'm really not sure if this is right, and please tell me where I got it wrong if I did.

16. $11x^{6} y^{5}$

17. $18a^{4} b^{6}$

I really hope this helps, and I feel really bad when someone asks me to help and I can't :((

5 0

3 years ago

Read 2 more answers

Two lines, C and D, are represented by the equations given below:

lys-0071 [83]

Bought lines need to pass same point, so:

x+12 = y = y = 3x+2
x+12=3x+2 |-2
x+10=3x |-x
10=2x |/2
5=x
x+12 = y => 5+12 = y =>y = 17

(x,y) => (5,17)

6 0

4 years ago

What is the measure of arc AC? Pls explain and I will mark brainliest!

atroni [7]

Answer:

D. 146°

Step-by-step explanation:

<u>Arcs in the circle sum to 360°</u>

Arc AB = 2*∠C = 2*(48°) = 96°
Arc BC = 138° - given
Arc AC = 360° - (96° + 118°) = 146°

7 0

3 years ago