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igomit [66]
3 years ago
5

Ps help me with this its urgent❤

Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:

y^6/x^2

Step-by-step explanation:

(y^3/2x^-1/2)^4= y^(4*3/2)x^(-1/2*4)=y^6x^-2= y^6/x^2

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let y be the distance between them, and x be the number of years that go by:
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We want to find where y = 0, where they meet:
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