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3 years ago

What is the answer to: 1-x >2x-2

1 answer:

5 0

$1 - x > 2x - 2$
Add x to both sides

$1 > 3x - 2$
Add 2 to both sides

$3 > 3x$
divide by 3 in both sides

$1 > x$
or
$x < 1$

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Plz answer this quickly i need this finished by tommorow

max2010maxim [7]

Answer:

The probability of landing on blue on spinner 1 is 3/8 theoretically. The probability of landing green on green on spinner 1 is 5/8 theoretically. The probability of landing on blue on spinner 2 is 2/6, which is 1/3. The probability of landing on either green or purple on spinner 2 is 3/6, or 1/2. The probability of landing on yellow on spinner 2 is 1/6. The probability of not landing on green on spinner 2 is 4/6, or 2/3. The experimental probability, you have to do, since only you can do that. So glad I can help, but can you please give me brainlist?

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3 years ago

How to determine if a graph is symmetrical

Lisa [10]

Answer:

If you fold it in half.

Step-by-step explanation:

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2 years ago

Read 2 more answers

BEING TIMED !! In circle O, the length of arc AB is 2(pi) and the radius is 5. Find the

inn [45]

Answer:

31.4

Step-by-step explanation:

3.14 x 2 x 5 = 31.4

8 0

2 years ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

2 years ago

-x^2+4x-8 axis of symmerty

V125BC [204]

Answer:

$\boxed {\boxed {\sf x=2}}$

Step-by-step explanation:

The axis of symmetry can be calculated using the formula:

$x=\frac{-b}{2a}$

First we must determine a and b from the quadratic: $-x^2+4x-8$ . This is in standard form, with the highest power first in descending order.

Standard form is also: $ax^2+bx+c$

If we compare this to the quadratic given, we can conclude that:

$a= -1 \\b= 4 \\c= -8$

Substitute the values for a and b into the formula.

$x= \frac{-(4)}{2(-1)}$

Multiply in the denominator.

$x=\frac {-4}{-2}$

Divide.

$x=2$

This can also be determined from the graph. It is the x-coordinate of the vertex or the maximum/minimum. It divides the quadratic into 2 symmetrical halves.

8 0

3 years ago