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e-lub [12.9K]
3 years ago
8

Guyscan you please help me on this question?

Mathematics
2 answers:
Galina-37 [17]3 years ago
7 0
19. B.
20. J.
Hope this helps :P
pav-90 [236]3 years ago
6 0

Answer:

ez

Step-by-step explanation:

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8 0
2 years ago
12x+7<-11 or 5x-8>40
puteri [66]

Answer:

\large\boxed{x9\dfrac{3}{5}\to x\in\left(-\infty,\ -1\dfrac{1}{2}\right)\ \cup\ \left(9\dfrac{3}{5},\ \infty\right)}

Step-by-step explanation:

12x+7

5x-8>40\qquad\text{add 8 to both sides}\\\\5x-8+8>40+8\\\\5x>48\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}>\dfrac{48}{5}\\\\x>\dfrac{48}{5}\\\\x>9\dfrac{3}{5}\\===========================

x9\dfrac{3}{5}

7 0
3 years ago
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