Find the x-component of this vector:

Mathematics

1 answer:

sashaice [31]4 years ago

4 0

Answer: -13.9

This value is approximate.

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Explanation:

This angle is in quadrant Q2, which is where x is negative and y is positive.

The angle shown of 65 degrees is added to the 90 degree angle to the right resulting in 65+90 = 155 degrees overall. See diagram below.

The x component of the vector is found by the formula

x = r*cos(theta)

we will plug in r = 15.3 as the magnitude of the vector and theta = 155 as the angle

x = 15.3*cos(155)

x = -13.8665 approximately

x = -13.9 rounding to one decimal place (as 15.3 and 65.0 are both rounded to one decimal place)

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Answer:

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