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tatiyna
3 years ago
14

Find the 59th term of the following arithmetic sequence. 15, 23, 31, 39

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0

15~~,~~\stackrel{15+8}{23}~~,~~\stackrel{23+8}{31}~~,~~\stackrel{31+8}{39}~~,~~...~\hspace{10em}\stackrel{common~difference}{d=8} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{59}\\ a_1=\stackrel{\textit{first term}}{15}\\ d=\stackrel{\textit{common difference}}{8} \end{cases} \\\\\\ a_{59}=15+(59-1)8\implies a_{59}=15+472-8\implies a_{59}=479

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Evaluate the expression when x=-5 <br> X^2 + 6x-9
d1i1m1o1n [39]

The value of the function f(x) = x² + 6x - 9 when x = -5 is  -14.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

Given that:

f(x) = x² + 6x - 9

When x = -5:

f(-5) = (-5)² + 6(-5) - 9 = -14

The value of the function f(x) = x² + 6x - 9 when x = -5 is  -14.

Find out more on equation at: brainly.com/question/2972832

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