Evaluate a(4b + c2) if a = 2, b = 5, and c = 1.
2 answers:
Answer:
The answer is 42 .
Step-by-step explanation:
Here,
a = 2
b = 5
c = 1
Now,


= 2( 20 + 1 )
= 2 x 21
=42
Answer:
42
Step-by-step explanation:
a = 2, b = 5, and c = 1
- a*(4b + c²) = ⇒ plug in values
- 2*(4*5 + 1²) = ⇒ solving exponents
- 2*(20 + 1) = ⇒ parenthesis
- 2*21 = ⇒ multiplication
- 42 ⇒ answer
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37 and 1 / 4 = 37 * 6 = 74 * 3 = 222
Answer:
5
Step-by-step explanation:
Answer:
Larger number = 34
Smaller number = 17
Step-by-step explanation:
Given that:
Sum of numbers = 51
Let,
x be the larger number
y be the smaller number
According to given statement;
x+y=51 Eqn 1
x = 2y Eqn 2
Putting x=2y in Eqn 1
2y+y=51
3y=51
Dividing both sides by 3

Putting y=17 in Eqn 2
x=2(17)
x=34
Hence,
Larger number = 34
Smaller number = 17
Answer:
B im pretty sure
Step-by-step explanation: