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alexandr402 [8]
3 years ago
13

Evaluate a(4b + c2) if a = 2, b = 5, and c = 1.

Mathematics
2 answers:
Svetach [21]3 years ago
4 0

Answer:

The answer is 42 .

Step-by-step explanation:

Here,

a = 2

b = 5

c = 1

Now,

 a(4b+c^{2} )

= 2(4 * 5 +1^{2} )

= 2( 20 + 1 )

= 2 x 21

=42

Maksim231197 [3]3 years ago
3 0

Answer:

42

Step-by-step explanation:

a = 2, b = 5, and c = 1

  • a*(4b + c²) =               ⇒ plug in values
  • 2*(4*5 + 1²) =              ⇒ solving exponents
  • 2*(20 + 1) =                 ⇒ parenthesis
  • 2*21 =                         ⇒ multiplication
  • 42                               ⇒ answer
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Answer:

x=333.33%

Step-by-step explanation:

hello

you can resolve this by using the rule of 3,let´s see

75 oranges =100%

250 oranges = x%?

75 oranges* x%=250 oranges *100%

x=\frac{250*100}{75}

x=333.33%

Have a great day.

4 0
2 years ago
Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg
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Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let <em>X</em> = number of college women on a diet.

The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.

The sample of women selected is, <em>n</em> = 267.

The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (\hat p) follows a Normal distribution.  

The mean of this distribution is:

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The standard deviation of this distribution is: \sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028

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P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z

**Use the <em>z</em>-table for the probability.

P(\hat p \geq 0.75)=1-P(Z

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

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Answer:

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