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GrogVix [38]
3 years ago
9

Find two consecutive even integers such that the sum of the numbers is ten more than the larger number. (Must solve algebraicall

y to receive full credit.)
Mathematics
1 answer:
hram777 [196]3 years ago
8 0

Answer:

10 and 12

Step-by-step explanation:

Let the smallest number = 2x

Then the larger number is 2x + 2

2x + 2x + 2 = 2x + 2 + 10                     Subtract 2x + 2 from both sides

2x = 10                                                  Divide by 2

x = 5

The smaller number is 2x = 2 * 5 = 10

The larger number is 2x + 2 = 12

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