First, we need to put the numbers in order...
58,60,69,71,78,78,85,85,86,87,88,91,93,95,95,95,96,98,100,100
and since there is an even number of numbers (20), we need to find the 2 middle numbers and divide them by 2 to find the median (Q2)
Q2 (the median) = (87 + 88) / 2 = 175/2 = 87.5
now we take all the numbers below 87.5...and find the median (middle number) and that number will be Q1...there is 2 middle numbers...so we add them and divide by 2
Q1 = (78 + 78) / 2 = 156/2 = 78
now we take all the numbers after 87.5....and find the median...there will be 2 numbers, so we add them and divide by 2..that wil be Q3
Q3 = (95 + 95) / 2 = 190/2 = 95
So in summary :
Q1 = 78 <==
Q2 = 87.5
Q3 = 95 <==
The interquartile range (IQR) is found by subtracting Q1 from Q3.
IQR = 95 - 78 = 17 <==
Answer:
Your answer is -14
Step-by-step explanation:
Answer:
Step-by-step explanation:
What is the VALUE OF 3r=10+5 when r=10?
substitute 10 for r in 3r=10+5. We get:
3(10) = 10 + 5, or 30 = 15. This equation is FALSE when r = 10.
You could solve the equation for r, however:
3r=10+5 becomes 3r = 15, and so r = 5. 5 is a solution; 10 is not a solution.
Answer:
f(x)=2(x-4)^2 = 4±√x/√2
Step-by-step explanation:
