The Jacobian for this transformation is

with determinant
, hence the area element becomes

Then the integral becomes

where
is the unit circle,

so that

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

Then

AABC has vertices at (1,5), (4,8), and (16, 12). A second triangle, ADEF, has vertices at (4, 20), (16, 32), and (64, 48). If th
navik [9.2K]
Answer: the first one
Step-by-step explanation:
(x,y)->(4x, 4y)
<h2><u>D:</u></h2><h2><em /></h2><h2><em>The awnser is </em><u><em>4</em></u><em>!! Hope this helps!! <3</em></h2>
Answer:
You need to draw a horizontal line that goes through the point (0,4).
Step-by-step explanation:
Slope of zero means it does not go up or down. It looks like this ↔, but stretched out to the two sides of the graph.