BRAINLIEST ASAP! PLEASE HELP ME :)

I need help with the top 3 plz

attashe74 [19]

Answer/Step-by-step explanation:

Recall: SOHCAHTOA

1. Reference angle = 70°

Adjacent side = x

Hypotenuse = 6 cm

Apply CAH. Thus,

Cos 70 = adj/hyp

Cos 70 = x/6

6 × cos 70 = x

2.05 = x

x = 2.05 cm

2. Reference angle = 45°

Adjacent side = x

Hypotenuse = 1.3 m

Applying CAH, we would have the following ratio:

Cos 45 = adj/hyp

Cos 45 = x/1.3

1.3 × cos 45 = x

0.92 = x

x = 0.92 m

3. The who diagram is not shown well. Some parts are missing, however you can still solve the problem just the same way we solved problem 1 and 2.

6 0

3 years ago

Find f'(x) and state the domain of f': f(x) = In (2x^2+1)

-Dominant- [34]

Answer:

$f'(x) = \frac{4x}{2x^2+1}$

Domain: All Real Numbers

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

f(x) = ln(2x² + 1)

Step 2: Differentiate

Derivative ln(u) [Chain Rule/Basic Power]: $f'(x) = \frac{1}{2x^2+1} \cdot 2 \cdot 2x^{2-1}$
Simplify: $f'(x) = \frac{1}{2x^2+1} \cdot 4x$
Multiply: $f'(x) = \frac{4x}{2x^2+1}$

Step 3: Domain

We know that we would have issues in the denominator when we have a rational expression. However, we can see that the denominator would never equal 0.

Therefore, our domain would be all real numbers.

We can also graph the differential function to analyze the domain.

5 0

3 years ago

Anderson has $50 in his savings account. He deposits $5 every week. His father also deposits $20 into the account every time And

Sav [38]

Part A: 5 is the coefficient, w is the variable, 50 is the constant

Part B: 10 x 5 = 50 + 2 x 20 = 40+ 50 = $140

Part C: the constant,50,would change and become 85. Hope this helps :)

8 0

3 years ago

Read 2 more answers

You have two exponential functions. One function has the formula g(x) = 5 x . The other function has the formula h(x) = 5-x . Wh

AVprozaik [17]

Given the exponential functions $g(x)= 5^{x}$ and $h(x)= 5^{-x}$

$k(x)=(g-h)(x)$
$k(x)=g(x)-h(x)
$
$k(x)= 5^{x} - 5^{-x}$
$k(x)= 5^{x} - \frac{1}{ 5^{x} }$
$k(x)= \frac{ 5^{x} 5^{x} }{ 5^{x} } - \frac{1}{ 5^{x} }$
$k(x)= \frac{ 5^{2x} }{ 5^{x} } - \frac{1}{ 5^{x} }$
$k(x)= \frac{ 5^{2x}-1 }{ 5^{x} }$

4 0

2 years ago

Read 2 more answers

2. Carissa also has a sink that is shaped like a half-sphere. The sink has a volume of 3617 in3. One day, her sink clogged. She

sleet_krkn [62]

Answer:Yes, your answers are correct.

The volume of a cone is given by V = 1/3πr²h. Since the diameter of the first cone is 4, the radius is 2; therefore the volume is

V = 1/3π(2²)(8) = 32π/3

We divide the volume of the sink, 2000π/3, by the volume of the cone:

2000π/3 ÷ 32π/3 = 2000π/3 × 3/32π = 6000π/96π = 62.5 ≈ 63.

The diameter of the second conical cup is 8, so the radius is 4. The volume then is:

V = 1/3π(4²)(8) = 128π/3

Dividing the volume of the sink, 2000π/3, by 128π/3:

2000π/3 ÷ 128π/3 = 2000π/3 × 3/128π = 6000π/384π = 15.625 ≈ 16

Step-by-step explanation:

8 0

2 years ago