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Alex_Xolod [135]
3 years ago
13

PLEASE HELP URGENT

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0
(10/17) / (-15/17) =
10/17 * - 17/15 =
- 10/15 =
- 2/5 <==
============
2.75 / -2.2 =
- 1.25 <==
============
(-2 3/5) / (3/5) =
- 13/5 * 5/3 =
-13/3 or - 4 1/3 <==
============
(2 1/4) / (3/4) =
9/4 * 4/3 =
9/3 =
3 <==
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9. Jackie invited 17 people to
daser333 [38]

Answer:

  27

Step-by-step explanation:

17 - 8 = 9 people came

The number of presents brought is 3×9 = 27.

Jackie got 27 presents.

4 0
3 years ago
on a coordinate grid, her house is located at (1,2) and the park at (5,5) what is the shortest distance from her house to the pa
nadya68 [22]
To solve, use the distance formula: d= \sqrt{(x_1+x_2)^2+(y_1+y_2)^2}. Using your values of x and y, you get d= \sqrt{(1+5)^2+(2+5)^2} = \sqrt{6^2+7^2} = \sqrt{36+49} = \sqrt{85}, which is approximately 9.22. This means your shortest distance is √85≈9.22
3 0
3 years ago
Given the following geometric sequence, find the common ratio:<br><br> {225, 45, 9...}
Tom [10]

Answer:

\frac{1}{5}  is the common ratio

Step-by-step explanation:

Common ratio(r) states that the ratio of each term of a geometric sequence to the term preceding it.

r = \frac{a_2}{a_1} =\frac{a_3}{a_2}........\frac{a_{n+1}}{a_n}

Given the sequence:

225, 45, 9, .........

Here,

a_1 = 225

a_2 = 45

a_3 = 9 and so on...

Using definition to find r.

r = \frac{45}{225}=\frac{9}{45}......

After solving we get;

r = \frac{1}{5}

Therefore, the common ratio is, \frac{1}{5}

8 0
3 years ago
Read 2 more answers
NNNNNNNNEED HELP!!!!!
Neko [114]

Answer: First box=3, second box=4, third box=0, last box=2

Step-by-step explanation: Do the math for the boxes.

5 0
3 years ago
A contractor purchases a shipment of 100 transistors. It is his policy to test 10 of these transistors and to keep the shipment
Serjik [45]

Answer:

Hence the probability of the at least 9 of 10 in working condition is 0.3630492

Step-by-step explanation:

Given:

total transistors=100

defective=20

To Find:

P(X≥9)=P(X=9)+P(X=10)

Solution:

There  are 20 defective and 80 working transistors.

Probability of at least 9 of 10 should be working out 80 working transistors

is given by,

P(X≥9)=P(X=9)+P(X=10)

<em>{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}</em>

P(X≥9)={80C9*20C(10-9)}/(100C10)+{80C10*20(10-10)}/(100C10)

<em>(Use the permutation and combination calculator)</em>

P(X≥9)=(231900297200*20/17310309456440)

+(1646492110120/17310309456440)

P(X≥9)=0.267933+0.0951162

P(X≥9)=0.3630492

4 0
3 years ago
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