M8 im not a computer be serious
Answer:
1000000
I would appreciate if my answer is chosen as a brainliest answer
AC/DF= BC/EF is the correct answer! :)
The two similar triangles are triangle BXY and triangle BAC. Since line XY is parallel to segment AC, angle BXY is congruent to angle A, and angle BYX is congruent to angle C. Since two corresponding angles are congruent, we use one of our similarity conjectures, Angle-Angle, to show these triangles are congruent.
---
Hope this helps!
