Instructions:Select the correct answer.

Compute the total resistance of a parallel circuit in which one branch has a resistance of 40 ohms and the other has a resistanc

HACTEHA [7]

Step-by-step explanation:

In the picture.

I hope that it's a clear solution and explanation.

8 0

3 years ago

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alisha [4.7K]

Answer:

$d=3\sqrt{2}\ units$

Step-by-step explanation:

The complete question is

Line L contains points (3, 5) and (7, 9). Points P has coordinates (2, 10). Find the distance from P to L

step 1

Find the equation of the line L contains points (3,5) and (7,9)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{9-5}{7-3}$

$m=\frac{4}{4}=1$

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=1\\point\ (3,5)$

substitute

$y-5=(1)(x-3)$

isolate the variable y

$y=x-3+5$

$y=x+2$ -----> equation A

step 2

Find the equation of the perpendicular line to the given line L that passes through the point P

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal

so

The slope of the given line L is $m=1$

The slope of the line perpendicular to the given line L is

$m=-1$

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=-1\\point\ (2,10)$

substitute

$y-10=-(x-2)$

isolate the variable y

$y=-x+2+10$

$y=-x+12$ ----> equation B

step 3

Find the intersection point equation A and equation B

$y=x+2$ -----> equation A

$y=-x+12$ ----> equation B

solve the system by graphing

The intersection point is (5.7)

see the attached figure

step 4

we know that

The distance from point P to the the line L is equal to the distance between the point P and point (5,7)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(2,10) and (5,7)

substitute

$d=\sqrt{(7-10)^{2}+(5-2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$d=\sqrt{18}\ units$

simplify

$d=3\sqrt{2}\ units$

see the attached figure to better understand the problem

6 0

3 years ago

You have 6 pints of glaze. It takes ⅞ of a pint to glaze a bowl and 9/16 of a pint to glaze a plate

Alex777 [14]

Your question is Incomplete

Is Your question this?

You have 6 pints of glaze. It takes 7/8 of a pint to glaze a bowl and 9/16 of a pint to glaze a plate.

A. How many bowls could you glaze

B. How many plates can you glaze

C. How much glaze will be left over?

If it is the Answer is below.

(If it not please tell me)

Answer/Step-by-step explanation:

Given:

6 Pints of glaze

takes 7/8 of pint to glaze a bowl

9/16 of a pint to glaze a plate

Part A) How many bowls could you glaze?

You have 6 pints of glaze. It takes 7/8 of a pint to glaze a bowl

so

To find the number of bowls divide 6 by 7/8

= 48/7 = 6.86 bowls

Therefore the answer to part A is equal to 6 bowls.

=================================================================

Part B) How many plates can you glaze?

You have 6 pints of glaze. It takes 9/16 of a pint to glaze a plate

so

To find the number of plates divide 6 by 9/16

=96/2 = 10.67 plates

Therefore the answer to part B is equal to 10 plates.

=================================================================

Part C) How much glaze will be left over?

$Part A =6-6*\frac{7}{8} =6-\frac{42}{8} =\frac{48}{8} = \frac{42}{8}=\frac{3}{4}$ pint of glazes left

$Part B=6-10*\frac{9}{16} =6-\frac{45}{8} =\frac{48}{8} -\frac{45}{8} =\frac{3}{8}$ pint of glazes left

4 0

3 years ago

Read 2 more answers

A 60-year-old man has a 4-year-old granddaughter. The man is how many times as old as his granddaughter? A) 15 times as old B) 2

nikdorinn [45]

Answer:

A) 15 times as old

Step-by-step explanation:

60/4=15

4 0

3 years ago

NEED HELP FOR THESE TWO THANKS !!!???

Dafna11 [192]

Answer:

$c$ , $h=78$

Step-by-step explanation:

$\frac{h}{6}=13$

$\frac{h}{6}*6=13*6$ Multiplication property of equality.

$h=78$ Simplify

$3c+5$

$3c+5-5$ Subtraction property of inequalities

$3c$ Simplify

$3c\div 3$ Division property of inequalities

$c$ Simplify

4 0

3 years ago