Answer:
The first question:
x = -1
Step-by-step explanation:
Step 1 :
Pulling out like terms :
1.1 Pull out like factors :
-x - 1 = -1 • (x + 1)
Equation at the end of step 1 :
Step 2 :
Solving a Single Variable Equation :
2.1 Solve : -x-1 = 0
Add 1 to both sides of the equation :
-x = 1
Multiply both sides of the equation by (-1) : x = -1
One solution was found :
x = -1
Processing ends successfully
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Do 45/225 and simplify and that’s your answer
Note that this just produces three parametric equations:
In the
plane, this is just he parametric equation for an ellipse (as a function of u). The z is simply a linear function.
The surface is then an ellipse extruded along the z-axis. We get a elliptic cylinder.
√(1 + √(1 - x²)) - √(1 - √(1 - x²))
√(1 + 1 - x) - √(1 - 1 - x)
√(2 - x) - √(0 - x)
(1.414 - x^1/2) - (0 - x^1/2)
1.414 - 0 - x^1/2 + x^1/2
1.414
What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.
How big can (t) get before water actually starts escaping the reservoir?
Essentially, to figure this out r(t) would have to be equal to 0.
700 - 40t = 0
40t=700
t=700/40=17.5
So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.
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The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
