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4 years ago

Which of the following is not a way to quality check a source?

Mathematics

2 answers:

DiKsa [7]4 years ago

6 0

Answer:

Popularity

Step-by-step explanation:

That many people like or have seen a source does not mean it is correct.

miss Akunina [59]4 years ago

3 0

Answer: Popularity

Step-by-step explanation:

Popularity is not a factor to consider while checking the quality of a source. Relevance Accuracy, Timeliness, Authority and Objectivity are factors to consider

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Gina has 5 2/6 feet of silver ribbon and 2 4/6 of gold ribbon

topjm [15]

Answer:

5 2/6 + 2 4/6 = 8

Step-by-step explanation:

So Gina has 8 feet of ribbon in total.

I hope this is what you were asking for!! :)

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Brainliest PLEASE!!?!?!?!??!?!!?!!?!?!?

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3 years ago

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

3 years ago

HELP HELP HELP HELP!!I WILL MARK BRAINLIEST IF CORRECT! Find the tangents of the acute angles in the right triangle. Write each

Softa [21]

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3 years ago

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4 years ago

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What is the value of h in the equation 8h = 60

irga5000 [103]

Answer:

h= 7.5

Step-by-step explanation:

8h=60

One solution was found :

h = 15/2 = 7.500

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

8*h-(60)=0

Step by step solution :

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

8h - 60 = 4 • (2h - 15)

Equation at the end of step 1 :

Step 2 :

Equations which are never true :

2.1 Solve : 4 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : 2h-15 = 0

Add 15 to both sides of the equation :

2h = 15

Divide both sides of the equation by 2:

h = 15/2 = 7.500

One solution was found :

h = 15/2 = 7.500

Processing ends successfully

7 0

3 years ago

Read 2 more answers