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DanielleElmas [232]
3 years ago
9

What is gif of 18 and 24

Mathematics
1 answer:
babunello [35]3 years ago
6 0

Answer:

6

Step-by-step explanation:

I assume you mean GCF, greatest common factor.

First, write the prime factorizations for each:

18 = 2¹ × 3²

24 = 2³ × 3¹

Next, find what they have in common.  Both have a factor of 2¹ and 3¹.

GCF = 2¹ × 3¹

GCF = 6

The greatest common factor is 6.

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HELP ME PLEASE!!! What is the value of y for the parallelogram shown A. 66 B. 60 C. 22 D. 38
Nesterboy [21]

Answer:

<h2><em>2</em><em>2</em></h2>

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<em>Solu</em><em>tion</em><em>,</em>

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<em>or  \: 3 \times y = 66 \\ or \: y =  \frac{66}{3}  \\ y = 22</em>

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5 0
3 years ago
Select all the exspressions that are all equivalent to 20 percent of 150
Dmitriy789 [7]

<em>Note: It seems you may have unintentionally missed adding the answer choices. Thus, I am solving your question in general to give you the idea of how the percentage works, which anyways would solve your query.</em>

<em></em>

Answer:

Please check the explanation.

Step-by-step explanation:

Given that we have to determine the expressions which are equivalent to 20 percent of 150.

First, we need to determine what actually 20 percent of 150 really brings.

i.e

20% of 150 = 20/100 × 150

                   = 30

Thus,

20% of 150 = 30

Therefore, any expression that is equivalent to 30 will be included in the answer to this question.

4 0
3 years ago
I need help ASAP PLEASE ASAP!!!
zysi [14]
The area is 10 just use a area calculator!
3 0
2 years ago
Read 2 more answers
800 grams is how many pounds
VashaNatasha [74]
2.2 lb is equivalent to 1 kg.  Therefore,

 800 grams      1 kg           2.2 lb
---------------- * ----------- * ------------ = 1.76 lb (answer)
          1           1000 g         1 kg
5 0
3 years ago
An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha
hodyreva [135]

Answer:

11196.15 km

Step-by-step explanation:

Consider the attached diagram

If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.

Using trigonometry

Tan \alpha =\frac{Opposite}{adjacent} \\Tan 15 =\frac{3000}{|AB|}

Cross multiply

|AB|X Tan 15 =3000

|AB| = \frac{3000}{Tan 15} =11196.15 km

Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km

6 0
3 years ago
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