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deff fn [24]
3 years ago
5

With direct variation, if you increase the input, the output

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0

Increases proportionally. (C)

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Please write the solution
GrogVix [38]

Answer:

D.

Step-by-step explanation:

that is the answer to the question above

3 0
2 years ago
One angle of a triangle has a measure of 36°. The measure of the third angle is 28° less than 3 times the measure of the second
Alex_Xolod [135]

Answer:

  1. Define your variable and write your equation:  36 + b + (3b-28) = 180°.
  2. measure of the second angle: 43°.
  3. measure of the third angle: 101°

Step-by-step explanation:

a = 36

c = 3b - 28

a + b + c = 180°

a = measure of the first angle

b = measure of the second angle

c = measure of the third angle

then:

1)  36 + b + (3b-28) = 180   ⇒ )Define your variable. Write your equation and solve)

b + 3b + 36 - 28 = 180

4b + 8 = 180

4b = 180 - 8

4b = 172

b = 172/4

2)   b = 43°        ⇒   measure of the second angle

c = 3b - 28

c = 3*43 - 28

c = 129 - 28

3) c = 101°      ⇒   measure of the third angle

Check:

36° + 43° + 101° = 180°

8 0
3 years ago
Help Please ????!!!?
blondinia [14]
Irrational numbers

hope this helped :)
5 0
3 years ago
Read 2 more answers
What is (6,2) rotation 270
nignag [31]

Given:

The point is (6,2).

To find:

The image of given point after rotation of 270 degrees.

Solution:

Let the given point be P(6,2).

Rotation of 270 degrees means the figure is rotated 270 degrees counterclockwise about the origin. So, the rule of rotation is

(x,y)\to (y,-x)

Using this rule, we get

P(6,2)\to P'(2,-6)

Therefore, the image of given point is (2,-6).

3 0
3 years ago
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Olegator [25]

Answer:

b+6

Problem:

If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?

Step-by-step explanation:

We are given (b+c)/2=8 and d=3b-4.

We are asked to find (c+d)/2 in terms of variable, b.

We need to first solve (b+c)/2=8 for c.

Multiply both sides by 2: b+c=16.

Subtract b on both sides: c=16-b

Now let's plug in c=16-b and d=3b-4 into (c+d)/2:

([16-b]+[3b-4])/2

Combine like terms:

(12+2b)/2

Divide top and bottom by 2:

(6+1b)/1

Multiplicative identity property applied:

(6+b)/1

Anything divided by 1 is that anything:

(6+b)

6+b

b+6

3 0
3 years ago
Read 2 more answers
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