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4 years ago

Solve the simultaneous equation x + y = 2 and 4y² - x²= 11

Business

1 answer:

riadik2000 [5.3K]4 years ago

4 0

Answer:

The solution sets are ( $\frac{1}{3},\frac{5}{3}$ ) and (5,-3)

Explanation:

We are given two equations and we are supposed to solve these two equations and find their solutions.

x + y = 2

4 $y^{2}-x^{2}=11$

Substitute the first equation in the second and make it a quadratic equation in one variable.

4 $y^{2}-(2-y)^{2}= 11$

4 $y^{2}-(y^{2}-4y+4)=11$

$3y^{2}+4y-4=11$

$3y^{2}+4y-15=$

$3y^{2}+9y-5y-15=0$

(3y-5)(y+3) = 0

y = $\frac{5}{3}$ or y = -3

x = $\frac{1}{3}$ or x = 5

The solution sets are ( $\frac{1}{3},\frac{5}{3}$ ) and (5,-3)

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Solve the simultaneous equation x + y = 2 and 4y² - x²= 11​

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