Assume you mean 3x^2 when you typed the question.
3x^2+14x+16=0
(3x+8)(x+2)=0
x=-8/3 or -2
Answer:
C
Step-by-step explanation:
Its C
The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,
</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}</span>
