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Mashcka [7]
3 years ago
13

What is 2 3/5 minus 1 1/7

Mathematics
2 answers:
docker41 [41]3 years ago
5 0
2 3/5-(1 1/7)= 51/35
= 1 16/35
tia_tia [17]3 years ago
4 0
Exact form: 51/35
<span>
</span>
Mixed Number Form: 
<span>1 16/35

H3Y was correct.</span>
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Given<br> f(x) = 3x + 10 and g(x) = x - 2, find f (g(5))<br> -10<br> 23<br> None of these.
azamat
Answer: None of these

Explanation:

f(g(5)) first let’s find g(5)

We know:
g(x) = x - 2
g(5) = 5 - 2
g(5) = 3

Thus, f(g(5)) = f(3) because g(5) = 3

=> f(3) = 3(3) + 10
=> f(3) = 9 + 10
=> f(3) = 19

Therefore, f(g(5)) = 19
4 0
3 years ago
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Jace has two number cubes the red cube has the following numbers on the faces 1,1,2,2,5,6 the blue number cube has the following
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Answer: Jace is true

Step-by-step explanation:

7 0
2 years ago
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What is the answer to 5(p+6)=8p
Alekssandra [29.7K]
5\left( p+6 \right) =8p\\ \\ 5p+30=8p\\ \\ 8p-5p=30

\\ \\ 3p=30\\ \\ \frac { 1 }{ 3 } \cdot 3p=\frac { 1 }{ 3 } \cdot 30\\ \\ p=10
4 0
2 years ago
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I need help) (only the answer) *links and wrong answers will be reorted*
scZoUnD [109]

Answer:

Volume of cuboid = 300 in³

Surface area of cuboid = 280 in²

Step-by-step explanation:

Given:

Length = 10 in

Width = 5 in

Height = 6 in

Find:

Volume of cuboid

Surface area of cuboid

Computation:

Volume of cuboid = [L][B][H]

Volume of cuboid = [10][5][6]

Volume of cuboid = 300 in³

Surface area of cuboid = 2[lb][bh][hl]

Surface area of cuboid = 2[(10)(5) + (5)(6) + (6)(10)]

Surface area of cuboid = 2[50 + 30 + 60]

Surface area of cuboid = 2[140]

Surface area of cuboid = 280 in²

4 0
2 years ago
Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.50ft.
Anarel [89]
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59

Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm

Given that the density of air at room temperature is 0.00118g/cm^3, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg

Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
7 0
2 years ago
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