Your answer is -5.
This is because, if you expand the single bracket, you get -6x -3a, and since the other side of the equals sign is -6x + 15, then you need to do 15 ÷ -3 = -5.

I hope this helps!

6 0

3 years ago

Bartholemew will draw with replacement 160 tickets at random from a box with five tickets [0, 0, 0, 1, 2]. Estimate the chance t

cupoosta [38]

Answer:

0.0786

Step-by-step explanation:

It is given that Bartholemew had drawn the replacement of 160 tickets.

There are five tickets = [0, 0, 0, 1, 2]

Now we need to find the estimate of the ticket that has 1 on it and it turns up on the 32 draws exactly.

Since the probability of the drawing 1 out of 5 tickets is given by, $\frac{1}{5} = 0.2$

So the binomial with the parameter of n = 160 and p = 0.2, we get

P (it turns up on exactly 32 draws) = P(X = 32)

Therefore,

$C(160, 32)\times (0.2)^{32}\times (0.8)^{160-32}$

= 0.0786

4 0

3 years ago