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Mars2501 [29]
3 years ago
5

Which statement describing ratios is true?

Mathematics
1 answer:
Scilla [17]3 years ago
7 0
Hey

D cause if you have 3 boys and 4 girls that's a ratio 
<span>
Ratio
the quantitative relation between two amounts showing the number of times one value contains or is contained within the othe
</span>
Hoped I Helped

You might be interested in
What is the measure of an angle of a regular polygon with nine sides?
Elden [556K]

Answer:

140 degrees

Step-by-step explanation:

To find the value of an internal angle within this polygon, we can just multiply the number of triangles by 180 ° , then divide by the number of internal angles, which is nine. Excellent! So the interior angle of a 9 -sided polygon is 140 ° .

7 0
3 years ago
Natasha, Peter and Malachy share ?56 in a ratio 1:1:2. How much money does each person get? Natasha: ?? Peter: ?? Malachy: ??
Ahat [919]

Answer:

Natasha = 1 x 14 = 14

Peter = 2 x 14 = 28

Malachy = 1 x 14 = 14

Step-by-step explanation:

Ratio 1:1:2 so 1 + 1 + 2 = 4

Natasha, Peter and Malachy share of 56 : 56/4 = 14

Natasha = 1 x 14 = 14

Peter = 2 x 14 = 28

Malachy = 1 x 14 = 14

3 0
3 years ago
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the resulting values to the corresponding l
belka [17]

The correct solution to the limits of x in the tiles can be seen below.

  • \mathbf{ \lim_{x \to 9^+} (\dfrac{|x-9|}{-x^2-34+387}) }\mathbf{ = -\dfrac{1}{52} }
  • \mathbf{ \lim_{x \to 8^-} (\dfrac{8-x}{|-x^2-63x+568|}) }\mathbf{=\dfrac{1}{79} }
  • \mathbf{ \lim_{x \to 7^+} (\dfrac{|-x^2-17x+168| }{x-7}) }= -31
  • \mathbf{ \lim_{x \to 6^-} (\dfrac{|x-6| }{-x^2-86x+552}) }\mathbf{ =\dfrac{1}{98}}

<h3>What are the corresponding limits of x?</h3>

The limits of x approaching a given number of a quadratic equation can be determined by knowing the value of x at that given number and substituting the value of x into the quadratic equation.

From the given diagram, we have:

1.

\mathbf{ \lim_{x \to 9^+} (\dfrac{|x-9|}{-x^2-34+387}) }

So, x - 9 is positive when x → 9⁺. Therefore, |x -9) = x - 9

\mathbf{ \lim_{x \to 9^+} (\dfrac{x-9}{-x^2-34+387}) }

Simplifying the quadratic equation, we have:

\mathbf{ \lim_{x \to 9^+} (-\dfrac{1}{x+43}) }

Replacing the value of x = 9

\mathbf{ = (-\dfrac{1}{9+43}) }

\mathbf{ = -\dfrac{1}{52} }

2.

\mathbf{ \lim_{x \to 8^-} (\dfrac{8-x}{|-x^2-63x+568|}) }

  • -x²-63x+568 is positive when x → 8⁻.

Thus |-x²-63x+568| = -x²-63x+568

\mathbf{ \lim_{x \to 8^-} (\dfrac{1}{x+71}) }

\mathbf{=\dfrac{1}{8+71} }

\mathbf{=\dfrac{1}{79} }

3.

\mathbf{ \lim_{x \to 7^+} (\dfrac{|-x^2-17x+168| }{x-7}) }

  • x -7 is positive, therefore |x-7| = x - 7

\mathbf{ \lim_{x \to 7^+} (\dfrac{-x^2-17x+168 }{x-7}) }

\mathbf{ \lim_{x \to 7^+} (-x-24)}

\mathbf{ \lim_{x \to 7^+} (-7-24)}

= -31

4.

\mathbf{ \lim_{x \to 6^-} (\dfrac{|x-6| }{-x^2-86x+552}) }

  • x-6 is negative when x → 6⁻. Therefore, |x-6| = -x + 6

\mathbf{ \lim_{x \to 6^-} (\dfrac{-x+6 }{-x^2-86x+552}) }

\mathbf{ \lim_{x \to 6^-} (\dfrac{1}{x+92}) }

\mathbf{ \lim_{x \to 6^-} (\dfrac{1}{6+92}) }

\mathbf{ =\dfrac{1}{98}}

Learn more about calculating the limits of x here:

brainly.com/question/1444047

#SPJ1

7 0
2 years ago
Hi. help me please<br>the question is in the picture<br>please answer it​
lana66690 [7]
<h2><u>MATH</u><u> </u><u>/</u><u>/</u><u> </u><u>ANSWER</u></h2>

Direction: Name the pair of Angles in each of the following. Write your answer on the space provided.

  • Pair of Complementary Angles

∠ASN & ∠NSG

∠ESA & ∠ASN

  • Pair of Supplementary Angles

∠GSL & ∠GSA

∠NSL & ∠ASN

∠NSL & ∠ESA

  • Line Pairs

∠GSL & ∠GSA

∠NSL & ∠ASN

HOPE THIS HELPS. GOODLUCK:)

3 0
3 years ago
Can you solve this? ;)
katen-ka-za [31]
Its A. multiply both sides by 3
6 0
3 years ago
Read 2 more answers
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