y is
. This is because in a 30-60-90 triangle, the side facing the 30° is always half of the side facing the 90°
x is always √3 times y, so x=24. Therefore, the answer is the second answer choice.
Answer:
![\frac{37}{42}](https://tex.z-dn.net/?f=%5Cfrac%7B37%7D%7B42%7D)
Step-by-step explanation:
Given :
![\frac{92.5}{105}](https://tex.z-dn.net/?f=%5Cfrac%7B92.5%7D%7B105%7D)
Multiply numerator and denominator by 2 :
![\frac{92.5}{105} \times\frac{2}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B92.5%7D%7B105%7D%20%5Ctimes%5Cfrac%7B2%7D%7B2%7D)
[Divide both sides by 5 as it is a common factor]
![\frac{185}{210} \div \frac{5}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B185%7D%7B210%7D%20%5Cdiv%20%5Cfrac%7B5%7D%7B5%7D)
Answer:
![\frac{6x}{18}](https://tex.z-dn.net/?f=%5Cfrac%7B6x%7D%7B18%7D)
Step-by-step explanation:
Answer:
Option B is the correct answer
Step-by-step explanation:
Hope it helps you in your learning process.
![\tan 30\degree=\frac{17}{x}](https://tex.z-dn.net/?f=%5Ctan%2030%5Cdegree%3D%5Cfrac%7B17%7D%7Bx%7D)
![\implies\frac{1}{\sqrt 3}=\frac{17}{x}](https://tex.z-dn.net/?f=%5Cimplies%5Cfrac%7B1%7D%7B%5Csqrt%203%7D%3D%5Cfrac%7B17%7D%7Bx%7D)
![\implies\huge{\red{ x={17\sqrt 3}}}](https://tex.z-dn.net/?f=%5Cimplies%5Chuge%7B%5Cred%7B%20x%3D%7B17%5Csqrt%203%7D%7D%7D)
![\sin 30\degree=\frac{17}{y}](https://tex.z-dn.net/?f=%5Csin%2030%5Cdegree%3D%5Cfrac%7B17%7D%7By%7D)
![\implies\frac{1}{2}=\frac{17}{y}](https://tex.z-dn.net/?f=%5Cimplies%5Cfrac%7B1%7D%7B2%7D%3D%5Cfrac%7B17%7D%7By%7D)
![\implies\huge{\purple{ y={34}}}](https://tex.z-dn.net/?f=%5Cimplies%5Chuge%7B%5Cpurple%7B%20y%3D%7B34%7D%7D%7D)
Answer:
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $470
r = 6% = 6/100 = 0.06
n = 1 because it was compounded once in a year.
Therefore, the equation used to determine the value of his bond after t years is
A = 470(1 + 0.06/1)^1 × t
A = 470(1.06)^t