Answer:
Idk what u mean by fraction but 80% of 15 is 12
Step-by-step explanation:
Y = 10x + 35
if y is cost per occupant and x is occupants, then we can read the equation as such:
Cost is equal to 10 times number of occupants plus a 35$ fee
10 times the number of occupants is the part we are worried about
The cost increases by 10$ for every occupant
Answer:
-1.023 + 5.6 = 4.58
Step-by-step explanation:
1. Drop the 3 in -1.023, becoming -1.02
2. Add 0 at the end of 5.6, becoming 5.60
3. Here is the problem you now solve:
-1.02 + 5.60. You can simply type this into your calculator. I hope this helped.
A Trapezoid needs to have one pair of sides parallel.
Two of the points already plotted have the same Y value ( 3)
So the 4th dot, should have the same Y value as the first dot, which is 1.
The 4th dot should be plotted at C (5,1)
∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
