–0.8b2+7.4b+(5.6b–0.2b2)

Mathematics

2 answers:

e-lub [12.9K]3 years ago

6 0

Answer:

Simplify the expression.

− 1b^{2}+ 13 b

Step-by-step explanation:

aev [14]3 years ago

5 0

In this question, you would be combining like terms

Solve by combining like terms:

-0.8b²+7.4b+(5.6b-0.2b²)

This is the same as:

-0.8b² + 7.4b + 5.6b - 0.2b²

Solve:

-0.8b² + 7.4b + 5.6b - 0.2b²

-1b² + 7.4b + 5.6b

-1b² + 13b

Answer:

-1b² + 13b

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A score that is three standard deviations above the mean would have a z score of

tia_tia [17]

The value of z-score for a score that is three standard deviations above the mean is 3.

In this question,

A z-score measures exactly how many standard deviations a data point is above or below the mean. It allows us to calculate the probability of a score occurring within our normal distribution and enables us to compare two scores that are from different normal distributions.

Let x be the score

let μ be the mean and

let σ be the standard deviations

Now, x = μ + 3σ

The formula of z-score is

$z_{score} = \frac{x-\mu}{\sigma}$