Answer:
1680 ways
Step-by-step explanation:
Total number of integers = 10
Number of integers to be selected = 6
Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.
<u>2 ways</u> <u>1 way</u> <u> </u> <u> </u> <u> </u> <u> </u>
Each of the line represent the digit in the integer.
After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840
Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways
Therefore, there are 1680 ways to pick six distinct integers.
Answer:
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
In the right triangle ABC find the length side BC
we know that
step 2
In the right triangle ABD find the length side BD
we know that
step 3
we know that
The distance between the two boats is the length side CD
substitute the values
On average a lamb weighs about 200 pounds,
so 12345678910 multiplied by 200 =<span>2.469135782e+12
</span>2.469135782e+12 divided by 2000 = <span>1234567891 tons</span>
98 days = (98 ⁄ 7) weeks = 14 weeks
<span>Po = initial population = 5 </span>
<span>Ƭ = doubling time in weeks </span>
<span>t = elapsed time in weeks </span>
<span>P{t} = population after "t" weeks </span>
<span> P{t} = (Po)•2^(t ⁄ Ƭ) </span>
<span> P{t} = (Po)•2^(t ⁄ 4) </span>
<span> P{t} = 5•2^(t ⁄ 4) </span>
<span> P{14} = (5)•2^(14 ⁄ 4) … t = 14 weeks = 98 days </span>
<span> P{14} = 56 … population after 14 weeks</span>
100 is the easiest because 1/100 =0.01
33/100=0.33
