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4 years ago

The exterior angles of a triangle measure x + 3, 2x + 1, and 3x - 4. Find the measure of each exterior angle.

Mathematics

1 answer:

jonny [76]4 years ago

5 0

The answer to the question is c

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If mc022-1.j pg and mc022-2.j pg, what is the value of (f – g)(144)? –84 –60 0 48

Mashutka [201]

Answer:

Step-by-step explanation:

f(x) = √(x) + 12

g(x) = 2√(x)

(f-g)(x) = √(x) + 12 - 2√(x)

(f-g)(x) = 12 - √(x)

if x = 144

(f-g)(144) = 12 - √(144) = 12 - 12 = 0

5 0

4 years ago

Read 2 more answers

Solve for x. Your answer must be simplified. -36 + X < 8

KIM [24]

First, you add 36 to both sides to get rid of -36. Then, the right side turns to 44 when add 8 and 36 together. Finally, your final answer is x<44

3 0

3 years ago

Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu

Sauron [17]

Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

$\mu = 15.0$

Standard deviation,

$\sigma = 1.25$

(1) P(X ≥ 17.5) = 1 - P( X ≤ 17.5)

$= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})$

$=1-P(z\leq \frac{17.5 - 15}{1.25})$

$=1-P(z\leq \frac{2.5}{1.25})$

$=1-P(z\leq 2)$

$=1- 0.5793$ ( By using z-score table )

= 0.4207

(2) P(14 ≤ X ≤ 18) = P(X ≤ 18) - P(X ≤ 14)

$=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})$

$=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})$

$=P(z\leq 2.4) - P(z\leq -0.8)$

= 0.9918 - 0.2119

= 0.7799

8 0

3 years ago

Give the reason for each statement in the proof. Statements may be used more than once and not all statements will be used.

svlad2 [7]

Answer:

1. Given

2. Given

3. Division property

4. Substitution

5. SSS similarity

Step-by-step explanation:

8 0

3 years ago

Perform the indicated operation and write the result in the form a+bi.

lesya692 [45]

Answer:

b) - 2 7 + i

Step-by-step explanation:

Explanation:-

Given 2 ( i -14) -i ( i+1)

= 2 i - 28 - i² - i

= 2 i - 28 - (-1) - i

= 2 i - 28 + 1 - i

= - 2 7 + i

5 0

3 years ago