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3 years ago

Rewrite 3x + 4y = 10 using function notation.

2 answers:

5 0

If you would like to rewrite 3 * x + 4 * y = 10 using function notation, you can do this using the following steps:

3 * x + 4 * y = 10
4 * y = 10 - 3 * x /4
y = 10/4 - 3/4 * x
y = 5/2 - 3/4 * x

The correct result would be y = 5/2 - 3/4 * x.

AveGali [126]3 years ago

5 0

3x+4y=10
4y=-3x+10
y=3/4x+5/2

f(x)=-3/4x+5/2
i believe let me double check my work

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Please help me!! I really need it!! I Could fail the 7th grade

babymother [125]

Answer:

Step-by-step explanation:

Price of one ticket = $4

Price of t tickets = 4t

1) 4t + 72 > 400

t > (400-72)/4

2) 4t + 72 > 400

4t + 72 - 72 > 400 - 72 {subtract 72 from both sides}

4t > 328

4t/4 > 328/4 {divide both sides by 4}

t > 82

7 0

3 years ago

Shapes A and B are similar.

kari74 [83]

The scale factor from A to B is 5/3 and the value of r is 33/5

<h3>The scale factor from A to B</h3>

From the figure, we have the following corresponding sides

A : B = 5 : 3

Express as fraction

B/A = 3/5

This means that, the scale factor from A to B is 5/3

<h3>The value of r</h3>

From the figure, we have the following corresponding sides

A : B = 11 : r

Express as fraction

B/A = r/11

Recall that:

B/A = 3/5

So, we have:

3/5 = r/11

Multiply by 11

r = 33/5

Hence, the value of r is 33/5

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3 0

2 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$