Solve simultaneously for both x and y: 2^x+1=4 and x^2+2y=31

1 answer:

5 0

Answer:

x= y:2^(x) +1 =4

x^(2) + 2y = 31

Step-by-step explanation:

You might be interested in

Lunna [17]

Answer:

Step-by-step explanation:

dunno

5 0

3 years ago

Stella [2.4K]

What are you asking is their a problem to it?

4 0

3 years ago

jenyasd209 [6]

Answer:

2(2) + 1 = 5

Step-by-step explanation:

6 0

3 years ago

const2013 [10]

Answer:

Step-by-step explanation:

$\frac{2 \frac{1}{2} }{\frac{2}{5} } = \frac{2\frac{1}{2} }{2} times 5$

1 1/4 × 5 = 6 1/4

3 0

3 years ago

Inessa05 [86]

Tim would have bought 11 sandwhiches and 15 sodas.

8 0

4 years ago

Solve simultaneously for both x and y: 2^x+1=4 and x^2+2y=31​