3 years ago

Solve simultaneously for both x and y: 2^x+1=4 and x^2+2y=31

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

5 0

Answer:

x= y:2^(x) +1 =4

x^(2) + 2y = 31

Step-by-step explanation:

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Solve simultaneously for both x and y: 2^x+1=4 and x^2+2y=31​

Solve simultaneously for both x and y: 2^x+1=4 and x^2+2y=31