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3 years ago

Find the distance between A and B. A) 7 units B) 6 units C) 5 units 7 units

Mathematics

2 answers:

tatyana61 [14]3 years ago

6 0

It’s 7 unites so I think it’s a

vova2212 [387]3 years ago

5 0

7 units
Because you count the each point on the graph till you get to eight. So down 3 to the right 4 which equals 7

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Algebra identify the pattern. Then write the next three terms in each sequence. 63,58,53,48.....

vovikov84 [41]

Answer:43, 38, 33

Step-by-step explanation:

The pattern is subtracting 5

63 -5 = 58

58 - 5 = 53

53 - 5 = 48

48 - 5 = 43

43 - 5 = 38

38 - 5 = 33

8 0

3 years ago

What is the area of triangle RFG?

vladimir1956 [14]

Answer: you're gonna need to tell us the measurements of the triangle or else we can't help you find the area

7 0

3 years ago

What is the simplified form of the following expression?

USPshnik [31]

Option C:

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

Solution:

Given expression is

$$\sqrt[3]{\frac{4 x}{5}}$

Note: $\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5$

To find the correct expression for the above simplified expression.

Option A: $\frac{\sqrt[3]{4 x}}{5}$

5 can be written as $\sqrt[3]{125}$ .

$$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{4x}{125} }$

It is not the given simplified expression.

Option B: $\frac{\sqrt[3]{20 x}}{5}$

$$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{20x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4x}{25} }$

It is not the given simplified expression.

Option C: $\frac{\sqrt[3]{100 x}}{5}$

$$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{100x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4 x}{5}}$

It is the given simplified expression.

Option D: $\frac{\sqrt[3]{100 x}}{125}$

$$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}$

It is not the given simplified expression.

Hence Option C is the correct answer.

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

3 0

3 years ago

Simplify the expression 5^3 x 5^-5

kotykmax [81]

Answer:

$\frac{1}{5^2}$ --- 1 over 5 squared

Step-by-step explanation:

When multiplying terms with a common base, you just add the exponents:

$x^a\times x^b=x^{a+ b}$

That's true even when you don't have any exponents.

$5\times5=5^1\times5^1=5^{1+1}=5^2=25$

$\rightarrow5^3\times5^{-5}\\\rightarrow5^{3-5}\\\rightarrow5^{-2}$

A negative exponent isn't fully simplified, so there's another rule to use:

$x^{-y}=\frac{1}{x^y}$

That is '1 over x to the y' if it's too small to read.

$\rightarrow5^{-2}=\frac{1}{5^2}$

4 0

2 years ago

Read 2 more answers

Hi, please help

SOVA2 [1]

Answer:

A. 133 degrees

Step-by-step explanation:

You add the two known interior numbers in the triangle to find the unknown exterior variable. In this case, the two known interior numbers are 83 and 50. 83 + 50 = 133

7 0

3 years ago